Average Error: 0.3 → 0.3
Time: 20.3s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r9745959 = x;
        double r9745960 = 27.0;
        double r9745961 = r9745959 * r9745960;
        double r9745962 = y;
        double r9745963 = r9745961 * r9745962;
        return r9745963;
}

double f(double x, double y) {
        double r9745964 = x;
        double r9745965 = 27.0;
        double r9745966 = r9745964 * r9745965;
        double r9745967 = y;
        double r9745968 = r9745966 * r9745967;
        return r9745968;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]
  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019172 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))