Average Error: 0.3 → 0.3
Time: 21.1s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r13911221 = x;
        double r13911222 = 27.0;
        double r13911223 = r13911221 * r13911222;
        double r13911224 = y;
        double r13911225 = r13911223 * r13911224;
        return r13911225;
}
↓
double f(double x, double y) {
        double r13911226 = x;
        double r13911227 = 27.0;
        double r13911228 = r13911226 * r13911227;
        double r13911229 = y;
        double r13911230 = r13911228 * r13911229;
        return r13911230;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019172 
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))