0.5 \cdot \sqrt{2 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2} \cdot 0.5double f(double re, double im) {
double r591810 = 0.5;
double r591811 = 2.0;
double r591812 = re;
double r591813 = r591812 * r591812;
double r591814 = im;
double r591815 = r591814 * r591814;
double r591816 = r591813 + r591815;
double r591817 = sqrt(r591816);
double r591818 = r591817 - r591812;
double r591819 = r591811 * r591818;
double r591820 = sqrt(r591819);
double r591821 = r591810 * r591820;
return r591821;
}
double f(double re, double im) {
double r591822 = re;
double r591823 = im;
double r591824 = hypot(r591822, r591823);
double r591825 = r591824 - r591822;
double r591826 = 2.0;
double r591827 = r591825 * r591826;
double r591828 = sqrt(r591827);
double r591829 = 0.5;
double r591830 = r591828 * r591829;
return r591830;
}



Bits error versus re



Bits error versus im
Results
Initial program 38.4
Simplified13.2
Final simplification13.2
herbie shell --seed 2019172 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))