Average Error: 0.3 → 0.3
Time: 21.9s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r10802822 = x;
        double r10802823 = 27.0;
        double r10802824 = r10802822 * r10802823;
        double r10802825 = y;
        double r10802826 = r10802824 * r10802825;
        return r10802826;
}

double f(double x, double y) {
        double r10802827 = x;
        double r10802828 = 27.0;
        double r10802829 = r10802827 * r10802828;
        double r10802830 = y;
        double r10802831 = r10802829 * r10802830;
        return r10802831;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]
  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019172 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))