Average Error: 0.0 → 0.0
Time: 6.1s
Precision: 64
\[0.0 \le x \le 2\]
\[x \cdot \left(x \cdot x\right) + x \cdot x\]
↓
\[x \cdot x + x \cdot \left(x \cdot x\right)\]
x \cdot \left(x \cdot x\right) + x \cdot x
↓
x \cdot x + x \cdot \left(x \cdot x\right)
double f(double x) {
        double r6133564 = x;
        double r6133565 = r6133564 * r6133564;
        double r6133566 = r6133564 * r6133565;
        double r6133567 = r6133566 + r6133565;
        return r6133567;
}
↓
double f(double x) {
        double r6133568 = x;
        double r6133569 = r6133568 * r6133568;
        double r6133570 = r6133568 * r6133569;
        double r6133571 = r6133569 + r6133570;
        return r6133571;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(\left(1 + x\right) \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(x \cdot x\right) + x \cdot x\]

  2. Final simplification0.0

    \[\leadsto x \cdot x + x \cdot \left(x \cdot x\right)\]

Reproduce

herbie shell --seed 2019172 
(FPCore (x)
  :name "Expression 3, p15"
  :pre (<= 0.0 x 2.0)

  :herbie-target
  (* (* (+ 1.0 x) x) x)

  (+ (* x (* x x)) (* x x)))