Average Error: 0.3 → 0.3
Time: 9.9s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r8666083 = x;
        double r8666084 = 27.0;
        double r8666085 = r8666083 * r8666084;
        double r8666086 = y;
        double r8666087 = r8666085 * r8666086;
        return r8666087;
}
↓
double f(double x, double y) {
        double r8666088 = x;
        double r8666089 = 27.0;
        double r8666090 = r8666088 * r8666089;
        double r8666091 = y;
        double r8666092 = r8666090 * r8666091;
        return r8666092;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019172 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))