Average Error: 29.3 → 0.3
Time: 19.5s
Precision: 64
\[e^{a \cdot x} - 1\]
\[\begin{array}{l} \mathbf{if}\;a \cdot x \le -0.07174886411196652880040147692852769978344:\\ \;\;\;\;\log \left(e^{e^{a \cdot x} - 1}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(a \cdot x + \left(\left(\left(a \cdot x\right) \cdot \left(a \cdot x\right)\right) \cdot \left(a \cdot \frac{1}{6}\right)\right) \cdot x\right) + \left(\left(a \cdot x\right) \cdot \left(a \cdot x\right)\right) \cdot \frac{1}{2}\\ \end{array}\]
e^{a \cdot x} - 1
\begin{array}{l}
\mathbf{if}\;a \cdot x \le -0.07174886411196652880040147692852769978344:\\
\;\;\;\;\log \left(e^{e^{a \cdot x} - 1}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(a \cdot x + \left(\left(\left(a \cdot x\right) \cdot \left(a \cdot x\right)\right) \cdot \left(a \cdot \frac{1}{6}\right)\right) \cdot x\right) + \left(\left(a \cdot x\right) \cdot \left(a \cdot x\right)\right) \cdot \frac{1}{2}\\

\end{array}
double f(double a, double x) {
        double r5591144 = a;
        double r5591145 = x;
        double r5591146 = r5591144 * r5591145;
        double r5591147 = exp(r5591146);
        double r5591148 = 1.0;
        double r5591149 = r5591147 - r5591148;
        return r5591149;
}

double f(double a, double x) {
        double r5591150 = a;
        double r5591151 = x;
        double r5591152 = r5591150 * r5591151;
        double r5591153 = -0.07174886411196653;
        bool r5591154 = r5591152 <= r5591153;
        double r5591155 = exp(r5591152);
        double r5591156 = 1.0;
        double r5591157 = r5591155 - r5591156;
        double r5591158 = exp(r5591157);
        double r5591159 = log(r5591158);
        double r5591160 = r5591152 * r5591152;
        double r5591161 = 0.16666666666666666;
        double r5591162 = r5591150 * r5591161;
        double r5591163 = r5591160 * r5591162;
        double r5591164 = r5591163 * r5591151;
        double r5591165 = r5591152 + r5591164;
        double r5591166 = 0.5;
        double r5591167 = r5591160 * r5591166;
        double r5591168 = r5591165 + r5591167;
        double r5591169 = r5591154 ? r5591159 : r5591168;
        return r5591169;
}

Error

Bits error versus a

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original29.3
Target0.2
Herbie0.3
\[\begin{array}{l} \mathbf{if}\;\left|a \cdot x\right| \lt 0.1000000000000000055511151231257827021182:\\ \;\;\;\;\left(a \cdot x\right) \cdot \left(1 + \left(\frac{a \cdot x}{2} + \frac{{\left(a \cdot x\right)}^{2}}{6}\right)\right)\\ \mathbf{else}:\\ \;\;\;\;e^{a \cdot x} - 1\\ \end{array}\]

Derivation

  1. Split input into 2 regimes
  2. if (* a x) < -0.07174886411196653

    1. Initial program 0.0

      \[e^{a \cdot x} - 1\]
    2. Using strategy rm
    3. Applied add-log-exp0.0

      \[\leadsto e^{a \cdot x} - \color{blue}{\log \left(e^{1}\right)}\]
    4. Applied add-log-exp0.0

      \[\leadsto \color{blue}{\log \left(e^{e^{a \cdot x}}\right)} - \log \left(e^{1}\right)\]
    5. Applied diff-log0.0

      \[\leadsto \color{blue}{\log \left(\frac{e^{e^{a \cdot x}}}{e^{1}}\right)}\]
    6. Simplified0.0

      \[\leadsto \log \color{blue}{\left(e^{e^{x \cdot a} - 1}\right)}\]

    if -0.07174886411196653 < (* a x)

    1. Initial program 44.2

      \[e^{a \cdot x} - 1\]
    2. Taylor expanded around 0 13.8

      \[\leadsto \color{blue}{\frac{1}{2} \cdot \left({a}^{2} \cdot {x}^{2}\right) + \left(a \cdot x + \frac{1}{6} \cdot \left({a}^{3} \cdot {x}^{3}\right)\right)}\]
    3. Simplified0.5

      \[\leadsto \color{blue}{\left(\left(x \cdot a\right) \cdot \left(x \cdot a\right)\right) \cdot \frac{1}{2} + x \cdot \left(\left(\frac{1}{6} \cdot a\right) \cdot \left(\left(x \cdot a\right) \cdot \left(x \cdot a\right)\right) + a\right)}\]
    4. Using strategy rm
    5. Applied distribute-lft-in0.5

      \[\leadsto \left(\left(x \cdot a\right) \cdot \left(x \cdot a\right)\right) \cdot \frac{1}{2} + \color{blue}{\left(x \cdot \left(\left(\frac{1}{6} \cdot a\right) \cdot \left(\left(x \cdot a\right) \cdot \left(x \cdot a\right)\right)\right) + x \cdot a\right)}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.3

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \cdot x \le -0.07174886411196652880040147692852769978344:\\ \;\;\;\;\log \left(e^{e^{a \cdot x} - 1}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(a \cdot x + \left(\left(\left(a \cdot x\right) \cdot \left(a \cdot x\right)\right) \cdot \left(a \cdot \frac{1}{6}\right)\right) \cdot x\right) + \left(\left(a \cdot x\right) \cdot \left(a \cdot x\right)\right) \cdot \frac{1}{2}\\ \end{array}\]

Reproduce

herbie shell --seed 2019172 
(FPCore (a x)
  :name "expax (section 3.5)"
  :herbie-expected 14

  :herbie-target
  (if (< (fabs (* a x)) 0.1) (* (* a x) (+ 1.0 (+ (/ (* a x) 2.0) (/ (pow (* a x) 2.0) 6.0)))) (- (exp (* a x)) 1.0))

  (- (exp (* a x)) 1.0))