Average Error: 0.0 → 0.0
Time: 3.6s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
\[\left(1 - x \cdot 0.5\right) \cdot x\]
x \cdot \left(1 - x \cdot 0.5\right)
\left(1 - x \cdot 0.5\right) \cdot x
double f(double x) {
        double r2428621 = x;
        double r2428622 = 1.0;
        double r2428623 = 0.5;
        double r2428624 = r2428621 * r2428623;
        double r2428625 = r2428622 - r2428624;
        double r2428626 = r2428621 * r2428625;
        return r2428626;
}

double f(double x) {
        double r2428627 = 1.0;
        double r2428628 = x;
        double r2428629 = 0.5;
        double r2428630 = r2428628 * r2428629;
        double r2428631 = r2428627 - r2428630;
        double r2428632 = r2428631 * r2428628;
        return r2428632;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]
  2. Final simplification0.0

    \[\leadsto \left(1 - x \cdot 0.5\right) \cdot x\]

Reproduce

herbie shell --seed 2019171 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  (* x (- 1.0 (* x 0.5))))