Average Error: 5.7 → 0
Time: 3.9s
Precision: 64
\[e^{\log a + \log b}\]
↓
\[b \cdot a\]
e^{\log a + \log b}
↓
b \cdot a
double f(double a, double b) {
        double r5733931 = a;
        double r5733932 = log(r5733931);
        double r5733933 = b;
        double r5733934 = log(r5733933);
        double r5733935 = r5733932 + r5733934;
        double r5733936 = exp(r5733935);
        return r5733936;
}
↓
double f(double a, double b) {
        double r5733937 = b;
        double r5733938 = a;
        double r5733939 = r5733937 * r5733938;
        return r5733939;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.7
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.7

    \[e^{\log a + \log b}\]

  2. Simplified0

    \[\leadsto \color{blue}{b \cdot a}\]

  3. Final simplification0

    \[\leadsto b \cdot a\]

Reproduce

herbie shell --seed 2019170 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))