0.5 \cdot \sqrt{2 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2} \cdot 0.5double f(double re, double im) {
double r902794 = 0.5;
double r902795 = 2.0;
double r902796 = re;
double r902797 = r902796 * r902796;
double r902798 = im;
double r902799 = r902798 * r902798;
double r902800 = r902797 + r902799;
double r902801 = sqrt(r902800);
double r902802 = r902801 - r902796;
double r902803 = r902795 * r902802;
double r902804 = sqrt(r902803);
double r902805 = r902794 * r902804;
return r902805;
}
double f(double re, double im) {
double r902806 = re;
double r902807 = im;
double r902808 = hypot(r902806, r902807);
double r902809 = r902808 - r902806;
double r902810 = 2.0;
double r902811 = r902809 * r902810;
double r902812 = sqrt(r902811);
double r902813 = 0.5;
double r902814 = r902812 * r902813;
return r902814;
}



Bits error versus re



Bits error versus im
Results
Initial program 38.8
Simplified13.1
Final simplification13.1
herbie shell --seed 2019170 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))