Average Error: 0.3 → 0.3
Time: 19.5s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r8429447 = x;
        double r8429448 = 27.0;
        double r8429449 = r8429447 * r8429448;
        double r8429450 = y;
        double r8429451 = r8429449 * r8429450;
        return r8429451;
}

double f(double x, double y) {
        double r8429452 = x;
        double r8429453 = 27.0;
        double r8429454 = r8429452 * r8429453;
        double r8429455 = y;
        double r8429456 = r8429454 * r8429455;
        return r8429456;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]
  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019169 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  (* (* x 27.0) y))