Average Error: 3.2 → 3.2
Time: 14.3s
Precision: 64
\[x \cdot \left(1.0 - y \cdot z\right)\]
\[\left(1.0 - z \cdot y\right) \cdot x\]
x \cdot \left(1.0 - y \cdot z\right)
\left(1.0 - z \cdot y\right) \cdot x
double f(double x, double y, double z) {
        double r9097869 = x;
        double r9097870 = 1.0;
        double r9097871 = y;
        double r9097872 = z;
        double r9097873 = r9097871 * r9097872;
        double r9097874 = r9097870 - r9097873;
        double r9097875 = r9097869 * r9097874;
        return r9097875;
}

double f(double x, double y, double z) {
        double r9097876 = 1.0;
        double r9097877 = z;
        double r9097878 = y;
        double r9097879 = r9097877 * r9097878;
        double r9097880 = r9097876 - r9097879;
        double r9097881 = x;
        double r9097882 = r9097880 * r9097881;
        return r9097882;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 3.2

    \[x \cdot \left(1.0 - y \cdot z\right)\]
  2. Using strategy rm
  3. Applied *-commutative3.2

    \[\leadsto \color{blue}{\left(1.0 - y \cdot z\right) \cdot x}\]
  4. Final simplification3.2

    \[\leadsto \left(1.0 - z \cdot y\right) \cdot x\]

Reproduce

herbie shell --seed 2019168 +o rules:numerics
(FPCore (x y z)
  :name "Data.Colour.RGBSpace.HSV:hsv from colour-2.3.3, I"
  (* x (- 1.0 (* y z))))