Average Error: 0.5 → 0.2
Time: 21.9s
Precision: 64
\[\frac{\left(\frac{\left(d1 \cdot \left(3\right)\right)}{\left(d1 \cdot d2\right)}\right)}{\left(d1 \cdot d3\right)}\]
↓
\[\left(\left(\mathsf{qma}\left(\left(\mathsf{qma}\left(\left(\left(3\right)\right), d3, \left(1.0\right)\right)\right), d2, \left(1.0\right)\right)\right)\right) \cdot d1\]
\frac{\left(\frac{\left(d1 \cdot \left(3\right)\right)}{\left(d1 \cdot d2\right)}\right)}{\left(d1 \cdot d3\right)}
↓
\left(\left(\mathsf{qma}\left(\left(\mathsf{qma}\left(\left(\left(3\right)\right), d3, \left(1.0\right)\right)\right), d2, \left(1.0\right)\right)\right)\right) \cdot d1
double f(double d1, double d2, double d3) {
        double r3513598 = d1;
        double r3513599 = 3.0;
        double r3513600 = /* ERROR: no posit support in C */;
        double r3513601 = r3513598 * r3513600;
        double r3513602 = d2;
        double r3513603 = r3513598 * r3513602;
        double r3513604 = r3513601 + r3513603;
        double r3513605 = d3;
        double r3513606 = r3513598 * r3513605;
        double r3513607 = r3513604 + r3513606;
        return r3513607;
}
↓
double f(double d1, double d2, double d3) {
        double r3513608 = 3.0;
        double r3513609 = /* ERROR: no posit support in C */;
        double r3513610 = /*Error: no posit support in C */;
        double r3513611 = d3;
        double r3513612 = 1.0;
        double r3513613 = /* ERROR: no posit support in C */;
        double r3513614 = /*Error: no posit support in C */;
        double r3513615 = d2;
        double r3513616 = /*Error: no posit support in C */;
        double r3513617 = /*Error: no posit support in C */;
        double r3513618 = d1;
        double r3513619 = r3513617 * r3513618;
        return r3513619;
}

Error

Bits error versus d1

Bits error versus d2

Bits error versus d3

Derivation

  1. Initial program 0.5

    \[\frac{\left(\frac{\left(d1 \cdot \left(3\right)\right)}{\left(d1 \cdot d2\right)}\right)}{\left(d1 \cdot d3\right)}\]

  2. Simplified0.3

    \[\leadsto \color{blue}{\left(\frac{\left(\frac{\left(3\right)}{d3}\right)}{d2}\right) \cdot d1}\]
  3. Using strategy rm

  4. Applied introduce-quire0.3

    \[\leadsto \left(\frac{\left(\frac{\color{blue}{\left(\left(\left(3\right)\right)\right)}}{d3}\right)}{d2}\right) \cdot d1\]

  5. Applied insert-quire-add0.3

    \[\leadsto \left(\frac{\color{blue}{\left(\left(\mathsf{qma}\left(\left(\left(3\right)\right), d3, \left(1.0\right)\right)\right)\right)}}{d2}\right) \cdot d1\]

  6. Applied insert-quire-add0.2

    \[\leadsto \color{blue}{\left(\left(\mathsf{qma}\left(\left(\mathsf{qma}\left(\left(\left(3\right)\right), d3, \left(1.0\right)\right)\right), d2, \left(1.0\right)\right)\right)\right)} \cdot d1\]

  7. Final simplification0.2

    \[\leadsto \left(\left(\mathsf{qma}\left(\left(\mathsf{qma}\left(\left(\left(3\right)\right), d3, \left(1.0\right)\right)\right), d2, \left(1.0\right)\right)\right)\right) \cdot d1\]

Reproduce

herbie shell --seed 2019164 +o rules:numerics
(FPCore (d1 d2 d3)
  :name "FastMath test3"
  (+.p16 (+.p16 (*.p16 d1 (real->posit16 3)) (*.p16 d1 d2)) (*.p16 d1 d3)))