0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r885506 = 0.5;
double r885507 = 2.0;
double r885508 = re;
double r885509 = r885508 * r885508;
double r885510 = im;
double r885511 = r885510 * r885510;
double r885512 = r885509 + r885511;
double r885513 = sqrt(r885512);
double r885514 = r885513 - r885508;
double r885515 = r885507 * r885514;
double r885516 = sqrt(r885515);
double r885517 = r885506 * r885516;
return r885517;
}
double f(double re, double im) {
double r885518 = re;
double r885519 = im;
double r885520 = hypot(r885518, r885519);
double r885521 = r885520 - r885518;
double r885522 = 2.0;
double r885523 = r885521 * r885522;
double r885524 = sqrt(r885523);
double r885525 = 0.5;
double r885526 = r885524 * r885525;
return r885526;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.3
Simplified13.1
Final simplification13.1
herbie shell --seed 2019164 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))