Average Error: 0.0 → 0.0
Time: 8.9s
Precision: 64
\[0 \le x \le 2\]
\[x \cdot \left(x \cdot x\right) + x \cdot x\]
\[x \cdot \left(x \cdot x + x\right)\]
x \cdot \left(x \cdot x\right) + x \cdot x
x \cdot \left(x \cdot x + x\right)
double f(double x) {
        double r4362300 = x;
        double r4362301 = r4362300 * r4362300;
        double r4362302 = r4362300 * r4362301;
        double r4362303 = r4362302 + r4362301;
        return r4362303;
}

double f(double x) {
        double r4362304 = x;
        double r4362305 = r4362304 * r4362304;
        double r4362306 = r4362305 + r4362304;
        double r4362307 = r4362304 * r4362306;
        return r4362307;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(\left(1.0 + x\right) \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(x \cdot x\right) + x \cdot x\]
  2. Using strategy rm
  3. Applied distribute-lft-out0.0

    \[\leadsto \color{blue}{x \cdot \left(x \cdot x + x\right)}\]
  4. Final simplification0.0

    \[\leadsto x \cdot \left(x \cdot x + x\right)\]

Reproduce

herbie shell --seed 2019164 
(FPCore (x)
  :name "Expression 3, p15"
  :pre (<= 0 x 2)

  :herbie-target
  (* (* (+ 1.0 x) x) x)

  (+ (* x (* x x)) (* x x)))