Average Error: 0.0 → 0.0
Time: 14.5s
Precision: 64
\[56789 \le a \le 98765 \land 0 \le b \le 1 \land 0 \le c \le 0.0016773 \land 0 \le d \le 0.0016773\]
\[a \cdot \left(\left(b + c\right) + d\right)\]
\[\left(\left(b + c\right) + d\right) \cdot a\]
a \cdot \left(\left(b + c\right) + d\right)
\left(\left(b + c\right) + d\right) \cdot a
double f(double a, double b, double c, double d) {
        double r4317664 = a;
        double r4317665 = b;
        double r4317666 = c;
        double r4317667 = r4317665 + r4317666;
        double r4317668 = d;
        double r4317669 = r4317667 + r4317668;
        double r4317670 = r4317664 * r4317669;
        return r4317670;
}

double f(double a, double b, double c, double d) {
        double r4317671 = b;
        double r4317672 = c;
        double r4317673 = r4317671 + r4317672;
        double r4317674 = d;
        double r4317675 = r4317673 + r4317674;
        double r4317676 = a;
        double r4317677 = r4317675 * r4317676;
        return r4317677;
}

Error

Bits error versus a

Bits error versus b

Bits error versus c

Bits error versus d

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[a \cdot b + a \cdot \left(c + d\right)\]

Derivation

  1. Initial program 0.0

    \[a \cdot \left(\left(b + c\right) + d\right)\]
  2. Final simplification0.0

    \[\leadsto \left(\left(b + c\right) + d\right) \cdot a\]

Reproduce

herbie shell --seed 2019164 
(FPCore (a b c d)
  :name "Expression, p14"
  :pre (and (<= 56789 a 98765) (<= 0 b 1) (<= 0 c 0.0016773) (<= 0 d 0.0016773))

  :herbie-target
  (+ (* a b) (* a (+ c d)))

  (* a (+ (+ b c) d)))