\frac{\left(\left(-b_2\right) - \left(\sqrt{\left(\left(b_2 \cdot b_2\right) - \left(a \cdot c\right)\right)}\right)\right)}{a}\frac{\left(-b_2\right) - \sqrt{\left(\mathsf{qms}\left(\left(\left(b_2 \cdot b_2\right)\right), a, c\right)\right)}}{a}double f(double a, double b_2, double c) {
double r1134709 = b_2;
double r1134710 = -r1134709;
double r1134711 = r1134709 * r1134709;
double r1134712 = a;
double r1134713 = c;
double r1134714 = r1134712 * r1134713;
double r1134715 = r1134711 - r1134714;
double r1134716 = sqrt(r1134715);
double r1134717 = r1134710 - r1134716;
double r1134718 = r1134717 / r1134712;
return r1134718;
}
double f(double a, double b_2, double c) {
double r1134719 = b_2;
double r1134720 = -r1134719;
double r1134721 = r1134719 * r1134719;
double r1134722 = /*Error: no posit support in C */;
double r1134723 = a;
double r1134724 = c;
double r1134725 = /*Error: no posit support in C */;
double r1134726 = /*Error: no posit support in C */;
double r1134727 = sqrt(r1134726);
double r1134728 = r1134720 - r1134727;
double r1134729 = r1134728 / r1134723;
return r1134729;
}



Bits error versus a



Bits error versus b_2



Bits error versus c
Initial program 1.7
rmApplied introduce-quire1.7
Applied insert-quire-fdp-sub1.7
Final simplification1.7
herbie shell --seed 2019163
(FPCore (a b_2 c)
:name "quad2m (problem 3.2.1, negative)"
(/.p16 (-.p16 (neg.p16 b_2) (sqrt.p16 (-.p16 (*.p16 b_2 b_2) (*.p16 a c)))) a))