Average Error: 0.0 → 0.0
Time: 14.1s
Precision: 64
\[x \cdot e^{y \cdot y}\]
↓
\[{\left(e^{y}\right)}^{y} \cdot x\]
x \cdot e^{y \cdot y}
↓
{\left(e^{y}\right)}^{y} \cdot x
double f(double x, double y) {
        double r37151312 = x;
        double r37151313 = y;
        double r37151314 = r37151313 * r37151313;
        double r37151315 = exp(r37151314);
        double r37151316 = r37151312 * r37151315;
        return r37151316;
}
↓
double f(double x, double y) {
        double r37151317 = y;
        double r37151318 = exp(r37151317);
        double r37151319 = pow(r37151318, r37151317);
        double r37151320 = x;
        double r37151321 = r37151319 * r37151320;
        return r37151321;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x \cdot {\left(e^{y}\right)}^{y}\]

Derivation

  1. Initial program 0.0

    \[x \cdot e^{y \cdot y}\]
  2. Using strategy rm

  3. Applied add-log-exp0.0

    \[\leadsto x \cdot e^{\color{blue}{\log \left(e^{y}\right)} \cdot y}\]

  4. Applied exp-to-pow0.0

    \[\leadsto x \cdot \color{blue}{{\left(e^{y}\right)}^{y}}\]

  5. Final simplification0.0

    \[\leadsto {\left(e^{y}\right)}^{y} \cdot x\]

Reproduce

herbie shell --seed 2019163 
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))