Average Error: 6.0 → 0.8
Time: 15.5s
Precision: 64
\[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y}\]
\[\begin{array}{l} \mathbf{if}\;y \le 0.06656101021950764:\\ \;\;\;\;x + \frac{1}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{1}{y \cdot e^{z}}\\ \end{array}\]
x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y}
\begin{array}{l}
\mathbf{if}\;y \le 0.06656101021950764:\\
\;\;\;\;x + \frac{1}{y}\\

\mathbf{else}:\\
\;\;\;\;x + \frac{1}{y \cdot e^{z}}\\

\end{array}
double f(double x, double y, double z) {
        double r20861375 = x;
        double r20861376 = y;
        double r20861377 = z;
        double r20861378 = r20861377 + r20861376;
        double r20861379 = r20861376 / r20861378;
        double r20861380 = log(r20861379);
        double r20861381 = r20861376 * r20861380;
        double r20861382 = exp(r20861381);
        double r20861383 = r20861382 / r20861376;
        double r20861384 = r20861375 + r20861383;
        return r20861384;
}

double f(double x, double y, double z) {
        double r20861385 = y;
        double r20861386 = 0.06656101021950764;
        bool r20861387 = r20861385 <= r20861386;
        double r20861388 = x;
        double r20861389 = 1.0;
        double r20861390 = r20861389 / r20861385;
        double r20861391 = r20861388 + r20861390;
        double r20861392 = z;
        double r20861393 = exp(r20861392);
        double r20861394 = r20861385 * r20861393;
        double r20861395 = r20861389 / r20861394;
        double r20861396 = r20861388 + r20861395;
        double r20861397 = r20861387 ? r20861391 : r20861396;
        return r20861397;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original6.0
Target1.1
Herbie0.8
\[\begin{array}{l} \mathbf{if}\;\frac{y}{z + y} \lt 7.1154157597908 \cdot 10^{-315}:\\ \;\;\;\;x + \frac{e^{\frac{-1}{z}}}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{e^{\log \left({\left(\frac{y}{y + z}\right)}^{y}\right)}}{y}\\ \end{array}\]

Derivation

  1. Split input into 2 regimes
  2. if y < 0.06656101021950764

    1. Initial program 7.7

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y}\]
    2. Taylor expanded around inf 1.2

      \[\leadsto x + \frac{e^{\color{blue}{0}}}{y}\]

    if 0.06656101021950764 < y

    1. Initial program 2.0

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y}\]
    2. Taylor expanded around inf 0.0

      \[\leadsto x + \color{blue}{\frac{e^{-1 \cdot z}}{y}}\]
    3. Simplified0.0

      \[\leadsto x + \color{blue}{\frac{e^{-z}}{y}}\]
    4. Using strategy rm
    5. Applied clear-num0.0

      \[\leadsto x + \color{blue}{\frac{1}{\frac{y}{e^{-z}}}}\]
    6. Simplified0.0

      \[\leadsto x + \frac{1}{\color{blue}{y \cdot e^{z}}}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.8

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \le 0.06656101021950764:\\ \;\;\;\;x + \frac{1}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{1}{y \cdot e^{z}}\\ \end{array}\]

Reproduce

herbie shell --seed 2019163 
(FPCore (x y z)
  :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, G"

  :herbie-target
  (if (< (/ y (+ z y)) 7.1154157597908e-315) (+ x (/ (exp (/ -1 z)) y)) (+ x (/ (exp (log (pow (/ y (+ y z)) y))) y)))

  (+ x (/ (exp (* y (log (/ y (+ z y))))) y)))