\frac{\left(\frac{\left(d1 \cdot \left(10\right)\right)}{\left(d1 \cdot d2\right)}\right)}{\left(d1 \cdot \left(20\right)\right)}\left(\mathsf{qma}\left(\left(\mathsf{qma}\left(\left(\left(d1 \cdot 10\right)\right), d1, d2\right)\right), d1, 20\right)\right)double f(double d1, double d2) {
double r6151029 = d1;
double r6151030 = 10.0;
double r6151031 = /* ERROR: no posit support in C */;
double r6151032 = r6151029 * r6151031;
double r6151033 = d2;
double r6151034 = r6151029 * r6151033;
double r6151035 = r6151032 + r6151034;
double r6151036 = 20.0;
double r6151037 = /* ERROR: no posit support in C */;
double r6151038 = r6151029 * r6151037;
double r6151039 = r6151035 + r6151038;
return r6151039;
}
double f(double d1, double d2) {
double r6151040 = d1;
double r6151041 = 10.0;
double r6151042 = r6151040 * r6151041;
double r6151043 = /*Error: no posit support in C */;
double r6151044 = d2;
double r6151045 = /*Error: no posit support in C */;
double r6151046 = 20.0;
double r6151047 = /*Error: no posit support in C */;
double r6151048 = /*Error: no posit support in C */;
return r6151048;
}



Bits error versus d1



Bits error versus d2
Initial program 0.3
rmApplied introduce-quire0.3
Applied insert-quire-fdp-add0.3
Applied insert-quire-fdp-add0.1
Final simplification0.1
herbie shell --seed 2019162 +o rules:numerics
(FPCore (d1 d2)
:name "FastMath test2"
(+.p16 (+.p16 (*.p16 d1 (real->posit16 10)) (*.p16 d1 d2)) (*.p16 d1 (real->posit16 20))))