\frac{\left(\left(-b_2\right) - \left(\sqrt{\left(\left(b_2 \cdot b_2\right) - \left(a \cdot c\right)\right)}\right)\right)}{a}\frac{\left(-b_2\right) - \sqrt{\left(\mathsf{qms}\left(\left(\left(b_2 \cdot b_2\right)\right), a, c\right)\right)}}{a}double f(double a, double b_2, double c) {
double r1321506 = b_2;
double r1321507 = -r1321506;
double r1321508 = r1321506 * r1321506;
double r1321509 = a;
double r1321510 = c;
double r1321511 = r1321509 * r1321510;
double r1321512 = r1321508 - r1321511;
double r1321513 = sqrt(r1321512);
double r1321514 = r1321507 - r1321513;
double r1321515 = r1321514 / r1321509;
return r1321515;
}
double f(double a, double b_2, double c) {
double r1321516 = b_2;
double r1321517 = -r1321516;
double r1321518 = r1321516 * r1321516;
double r1321519 = /*Error: no posit support in C */;
double r1321520 = a;
double r1321521 = c;
double r1321522 = /*Error: no posit support in C */;
double r1321523 = /*Error: no posit support in C */;
double r1321524 = sqrt(r1321523);
double r1321525 = r1321517 - r1321524;
double r1321526 = r1321525 / r1321520;
return r1321526;
}



Bits error versus a



Bits error versus b_2



Bits error versus c
Initial program 1.7
rmApplied introduce-quire1.7
Applied insert-quire-fdp-sub1.7
Final simplification1.7
herbie shell --seed 2019158
(FPCore (a b_2 c)
:name "quad2m (problem 3.2.1, negative)"
(/.p16 (-.p16 (neg.p16 b_2) (sqrt.p16 (-.p16 (*.p16 b_2 b_2) (*.p16 a c)))) a))