Average Error: 5.7 → 0
Time: 4.7s
Precision: 64
\[e^{\log a + \log b}\]
↓
\[b \cdot a\]
e^{\log a + \log b}
↓
b \cdot a
double f(double a, double b) {
        double r9436420 = a;
        double r9436421 = log(r9436420);
        double r9436422 = b;
        double r9436423 = log(r9436422);
        double r9436424 = r9436421 + r9436423;
        double r9436425 = exp(r9436424);
        return r9436425;
}
↓
double f(double a, double b) {
        double r9436426 = b;
        double r9436427 = a;
        double r9436428 = r9436426 * r9436427;
        return r9436428;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.7
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.7

    \[e^{\log a + \log b}\]

  2. Simplified0

    \[\leadsto \color{blue}{b \cdot a}\]

  3. Final simplification0

    \[\leadsto b \cdot a\]

Reproduce

herbie shell --seed 2019158 
(FPCore (a b)
  :name "Exp of sum of logs"

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))