\frac{\left(\frac{\left(d1 \cdot \left(10\right)\right)}{\left(d1 \cdot d2\right)}\right)}{\left(d1 \cdot \left(20\right)\right)}\left(\mathsf{qma}\left(\left(\mathsf{qma}\left(\left(\left(d1 \cdot 10\right)\right), d1, d2\right)\right), \left(d1 \cdot 20\right), 1.0\right)\right)double f(double d1, double d2) {
double r1201027 = d1;
double r1201028 = 10.0;
double r1201029 = /* ERROR: no posit support in C */;
double r1201030 = r1201027 * r1201029;
double r1201031 = d2;
double r1201032 = r1201027 * r1201031;
double r1201033 = r1201030 + r1201032;
double r1201034 = 20.0;
double r1201035 = /* ERROR: no posit support in C */;
double r1201036 = r1201027 * r1201035;
double r1201037 = r1201033 + r1201036;
return r1201037;
}
double f(double d1, double d2) {
double r1201038 = d1;
double r1201039 = 10.0;
double r1201040 = r1201038 * r1201039;
double r1201041 = /*Error: no posit support in C */;
double r1201042 = d2;
double r1201043 = /*Error: no posit support in C */;
double r1201044 = 20.0;
double r1201045 = r1201038 * r1201044;
double r1201046 = 1.0;
double r1201047 = /*Error: no posit support in C */;
double r1201048 = /*Error: no posit support in C */;
return r1201048;
}



Bits error versus d1



Bits error versus d2
Initial program 0.3
rmApplied introduce-quire0.3
Applied insert-quire-fdp-add0.3
Applied insert-quire-add0.2
Final simplification0.2
herbie shell --seed 2019156 +o rules:numerics
(FPCore (d1 d2)
:name "FastMath test2"
(+.p16 (+.p16 (*.p16 d1 (real->posit16 10)) (*.p16 d1 d2)) (*.p16 d1 (real->posit16 20))))