Average Error: 0.0 → 0.0
Time: 5.7s
Precision: 64
\[56789 \le a \le 98765 \land 0 \le b \le 1 \land 0 \le c \le 0.0016773 \land 0 \le d \le 0.0016773\]
\[a \cdot \left(\left(b + c\right) + d\right)\]
\[\left(\left(b + c\right) + d\right) \cdot a\]
a \cdot \left(\left(b + c\right) + d\right)
\left(\left(b + c\right) + d\right) \cdot a
double f(double a, double b, double c, double d) {
        double r1730688 = a;
        double r1730689 = b;
        double r1730690 = c;
        double r1730691 = r1730689 + r1730690;
        double r1730692 = d;
        double r1730693 = r1730691 + r1730692;
        double r1730694 = r1730688 * r1730693;
        return r1730694;
}

double f(double a, double b, double c, double d) {
        double r1730695 = b;
        double r1730696 = c;
        double r1730697 = r1730695 + r1730696;
        double r1730698 = d;
        double r1730699 = r1730697 + r1730698;
        double r1730700 = a;
        double r1730701 = r1730699 * r1730700;
        return r1730701;
}

Error

Bits error versus a

Bits error versus b

Bits error versus c

Bits error versus d

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[a \cdot b + a \cdot \left(c + d\right)\]

Derivation

  1. Initial program 0.0

    \[a \cdot \left(\left(b + c\right) + d\right)\]
  2. Final simplification0.0

    \[\leadsto \left(\left(b + c\right) + d\right) \cdot a\]

Reproduce

herbie shell --seed 2019156 
(FPCore (a b c d)
  :name "Expression, p14"
  :pre (and (<= 56789 a 98765) (<= 0 b 1) (<= 0 c 0.0016773) (<= 0 d 0.0016773))

  :herbie-target
  (+ (* a b) (* a (+ c d)))

  (* a (+ (+ b c) d)))