Average Error: 0.0 → 0.0
Time: 4.6s
Precision: 64
\[0 \le x \le 2\]
\[x \cdot \left(x \cdot x\right) + x \cdot x\]
↓
\[x \cdot x + x \cdot \left(x \cdot x\right)\]
x \cdot \left(x \cdot x\right) + x \cdot x
↓
x \cdot x + x \cdot \left(x \cdot x\right)
double f(double x) {
        double r1786409 = x;
        double r1786410 = r1786409 * r1786409;
        double r1786411 = r1786409 * r1786410;
        double r1786412 = r1786411 + r1786410;
        return r1786412;
}
↓
double f(double x) {
        double r1786413 = x;
        double r1786414 = r1786413 * r1786413;
        double r1786415 = r1786413 * r1786414;
        double r1786416 = r1786414 + r1786415;
        return r1786416;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(\left(1.0 + x\right) \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(x \cdot x\right) + x \cdot x\]

  2. Final simplification0.0

    \[\leadsto x \cdot x + x \cdot \left(x \cdot x\right)\]

Reproduce

herbie shell --seed 2019154 
(FPCore (x)
  :name "Expression 3, p15"
  :pre (<= 0 x 2)

  :herbie-target
  (* (* (+ 1.0 x) x) x)

  (+ (* x (* x x)) (* x x)))