Average Error: 38.7 → 0.0
Time: 2.6s
Precision: 64
\[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
\[x \cdot \left(2 + x\right)\]
\left(x + 1\right) \cdot \left(x + 1\right) - 1
x \cdot \left(2 + x\right)
double f(double x) {
        double r49457 = x;
        double r49458 = 1.0;
        double r49459 = r49457 + r49458;
        double r49460 = r49459 * r49459;
        double r49461 = r49460 - r49458;
        return r49461;
}

double f(double x) {
        double r49462 = x;
        double r49463 = 2.0;
        double r49464 = r49463 + r49462;
        double r49465 = r49462 * r49464;
        return r49465;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 38.7

    \[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
  2. Simplified0.0

    \[\leadsto \color{blue}{x \cdot \left(x + 2\right)}\]
  3. Final simplification0.0

    \[\leadsto x \cdot \left(2 + x\right)\]

Reproduce

herbie shell --seed 2019153 +o rules:numerics
(FPCore (x)
  :name "Expanding a square"
  (- (* (+ x 1) (+ x 1)) 1))