Average Error: 39.4 → 0.3
Time: 11.6s
Precision: 64
\[\frac{e^{x} - 1}{x}\]
\[\begin{array}{l} \mathbf{if}\;x \le -0.00010173923815578526:\\ \;\;\;\;\frac{-1 + e^{x + x}}{x + x \cdot \left(e^{x + x} \cdot e^{x}\right)} \cdot \left(\left(1 - e^{x}\right) + \sqrt[3]{e^{x}} \cdot \left(e^{x} \cdot \left(\sqrt[3]{e^{x}} \cdot \sqrt[3]{e^{x}}\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(\frac{1}{2} + x \cdot \frac{1}{6}\right) + 1\\ \end{array}\]
\frac{e^{x} - 1}{x}
\begin{array}{l}
\mathbf{if}\;x \le -0.00010173923815578526:\\
\;\;\;\;\frac{-1 + e^{x + x}}{x + x \cdot \left(e^{x + x} \cdot e^{x}\right)} \cdot \left(\left(1 - e^{x}\right) + \sqrt[3]{e^{x}} \cdot \left(e^{x} \cdot \left(\sqrt[3]{e^{x}} \cdot \sqrt[3]{e^{x}}\right)\right)\right)\\

\mathbf{else}:\\
\;\;\;\;x \cdot \left(\frac{1}{2} + x \cdot \frac{1}{6}\right) + 1\\

\end{array}
double f(double x) {
        double r1749407 = x;
        double r1749408 = exp(r1749407);
        double r1749409 = 1.0;
        double r1749410 = r1749408 - r1749409;
        double r1749411 = r1749410 / r1749407;
        return r1749411;
}

double f(double x) {
        double r1749412 = x;
        double r1749413 = -0.00010173923815578526;
        bool r1749414 = r1749412 <= r1749413;
        double r1749415 = -1.0;
        double r1749416 = r1749412 + r1749412;
        double r1749417 = exp(r1749416);
        double r1749418 = r1749415 + r1749417;
        double r1749419 = exp(r1749412);
        double r1749420 = r1749417 * r1749419;
        double r1749421 = r1749412 * r1749420;
        double r1749422 = r1749412 + r1749421;
        double r1749423 = r1749418 / r1749422;
        double r1749424 = 1.0;
        double r1749425 = r1749424 - r1749419;
        double r1749426 = cbrt(r1749419);
        double r1749427 = r1749426 * r1749426;
        double r1749428 = r1749419 * r1749427;
        double r1749429 = r1749426 * r1749428;
        double r1749430 = r1749425 + r1749429;
        double r1749431 = r1749423 * r1749430;
        double r1749432 = 0.5;
        double r1749433 = 0.16666666666666666;
        double r1749434 = r1749412 * r1749433;
        double r1749435 = r1749432 + r1749434;
        double r1749436 = r1749412 * r1749435;
        double r1749437 = r1749436 + r1749424;
        double r1749438 = r1749414 ? r1749431 : r1749437;
        return r1749438;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original39.4
Target38.6
Herbie0.3
\[\begin{array}{l} \mathbf{if}\;x \lt 1 \land x \gt -1:\\ \;\;\;\;\frac{e^{x} - 1}{\log \left(e^{x}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{x} - 1}{x}\\ \end{array}\]

Derivation

  1. Split input into 2 regimes
  2. if x < -0.00010173923815578526

    1. Initial program 0.1

      \[\frac{e^{x} - 1}{x}\]
    2. Using strategy rm
    3. Applied flip--0.1

      \[\leadsto \frac{\color{blue}{\frac{e^{x} \cdot e^{x} - 1 \cdot 1}{e^{x} + 1}}}{x}\]
    4. Applied associate-/l/0.1

      \[\leadsto \color{blue}{\frac{e^{x} \cdot e^{x} - 1 \cdot 1}{x \cdot \left(e^{x} + 1\right)}}\]
    5. Using strategy rm
    6. Applied flip3-+0.1

      \[\leadsto \frac{e^{x} \cdot e^{x} - 1 \cdot 1}{x \cdot \color{blue}{\frac{{\left(e^{x}\right)}^{3} + {1}^{3}}{e^{x} \cdot e^{x} + \left(1 \cdot 1 - e^{x} \cdot 1\right)}}}\]
    7. Applied associate-*r/0.1

      \[\leadsto \frac{e^{x} \cdot e^{x} - 1 \cdot 1}{\color{blue}{\frac{x \cdot \left({\left(e^{x}\right)}^{3} + {1}^{3}\right)}{e^{x} \cdot e^{x} + \left(1 \cdot 1 - e^{x} \cdot 1\right)}}}\]
    8. Applied associate-/r/0.1

      \[\leadsto \color{blue}{\frac{e^{x} \cdot e^{x} - 1 \cdot 1}{x \cdot \left({\left(e^{x}\right)}^{3} + {1}^{3}\right)} \cdot \left(e^{x} \cdot e^{x} + \left(1 \cdot 1 - e^{x} \cdot 1\right)\right)}\]
    9. Simplified0.1

      \[\leadsto \color{blue}{\frac{e^{x + x} + -1}{\left(e^{x + x} \cdot e^{x}\right) \cdot x + x}} \cdot \left(e^{x} \cdot e^{x} + \left(1 \cdot 1 - e^{x} \cdot 1\right)\right)\]
    10. Using strategy rm
    11. Applied add-cube-cbrt0.1

      \[\leadsto \frac{e^{x + x} + -1}{\left(e^{x + x} \cdot e^{x}\right) \cdot x + x} \cdot \left(e^{x} \cdot \color{blue}{\left(\left(\sqrt[3]{e^{x}} \cdot \sqrt[3]{e^{x}}\right) \cdot \sqrt[3]{e^{x}}\right)} + \left(1 \cdot 1 - e^{x} \cdot 1\right)\right)\]
    12. Applied associate-*r*0.1

      \[\leadsto \frac{e^{x + x} + -1}{\left(e^{x + x} \cdot e^{x}\right) \cdot x + x} \cdot \left(\color{blue}{\left(e^{x} \cdot \left(\sqrt[3]{e^{x}} \cdot \sqrt[3]{e^{x}}\right)\right) \cdot \sqrt[3]{e^{x}}} + \left(1 \cdot 1 - e^{x} \cdot 1\right)\right)\]

    if -0.00010173923815578526 < x

    1. Initial program 60.3

      \[\frac{e^{x} - 1}{x}\]
    2. Taylor expanded around 0 0.5

      \[\leadsto \color{blue}{\frac{1}{2} \cdot x + \left(\frac{1}{6} \cdot {x}^{2} + 1\right)}\]
    3. Simplified0.5

      \[\leadsto \color{blue}{1 + x \cdot \left(\frac{1}{6} \cdot x + \frac{1}{2}\right)}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.3

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \le -0.00010173923815578526:\\ \;\;\;\;\frac{-1 + e^{x + x}}{x + x \cdot \left(e^{x + x} \cdot e^{x}\right)} \cdot \left(\left(1 - e^{x}\right) + \sqrt[3]{e^{x}} \cdot \left(e^{x} \cdot \left(\sqrt[3]{e^{x}} \cdot \sqrt[3]{e^{x}}\right)\right)\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot \left(\frac{1}{2} + x \cdot \frac{1}{6}\right) + 1\\ \end{array}\]

Reproduce

herbie shell --seed 2019153 
(FPCore (x)
  :name "Kahan's exp quotient"

  :herbie-target
  (if (and (< x 1) (> x -1)) (/ (- (exp x) 1) (log (exp x))) (/ (- (exp x) 1) x))

  (/ (- (exp x) 1) x))