\frac{\tan^{-1}_* \frac{im}{re} \cdot \log base - \log \left(\sqrt{re \cdot re + im \cdot im}\right) \cdot 0}{\log base \cdot \log base + 0 \cdot 0}\frac{1}{\log base} \cdot \tan^{-1}_* \frac{im}{re}double f(double re, double im, double base) {
double r1039594 = im;
double r1039595 = re;
double r1039596 = atan2(r1039594, r1039595);
double r1039597 = base;
double r1039598 = log(r1039597);
double r1039599 = r1039596 * r1039598;
double r1039600 = r1039595 * r1039595;
double r1039601 = r1039594 * r1039594;
double r1039602 = r1039600 + r1039601;
double r1039603 = sqrt(r1039602);
double r1039604 = log(r1039603);
double r1039605 = 0.0;
double r1039606 = r1039604 * r1039605;
double r1039607 = r1039599 - r1039606;
double r1039608 = r1039598 * r1039598;
double r1039609 = r1039605 * r1039605;
double r1039610 = r1039608 + r1039609;
double r1039611 = r1039607 / r1039610;
return r1039611;
}
double f(double re, double im, double base) {
double r1039612 = 1.0;
double r1039613 = base;
double r1039614 = log(r1039613);
double r1039615 = r1039612 / r1039614;
double r1039616 = im;
double r1039617 = re;
double r1039618 = atan2(r1039616, r1039617);
double r1039619 = r1039615 * r1039618;
return r1039619;
}



Bits error versus re



Bits error versus im



Bits error versus base
Results
Initial program 30.8
Simplified0.3
rmApplied div-inv0.4
Final simplification0.4
herbie shell --seed 2019153
(FPCore (re im base)
:name "math.log/2 on complex, imaginary part"
(/ (- (* (atan2 im re) (log base)) (* (log (sqrt (+ (* re re) (* im im)))) 0)) (+ (* (log base) (log base)) (* 0 0))))