\frac{\left(\frac{\left(-b_2\right)}{\left(\sqrt{\left(\left(b_2 \cdot b_2\right) - \left(a \cdot c\right)\right)}\right)}\right)}{a}\frac{\sqrt{b_2 \cdot b_2 - c \cdot a} - b_2}{a}double f(double a, double b_2, double c) {
double r282592 = b_2;
double r282593 = -r282592;
double r282594 = r282592 * r282592;
double r282595 = a;
double r282596 = c;
double r282597 = r282595 * r282596;
double r282598 = r282594 - r282597;
double r282599 = sqrt(r282598);
double r282600 = r282593 + r282599;
double r282601 = r282600 / r282595;
return r282601;
}
double f(double a, double b_2, double c) {
double r282602 = b_2;
double r282603 = r282602 * r282602;
double r282604 = c;
double r282605 = a;
double r282606 = r282604 * r282605;
double r282607 = r282603 - r282606;
double r282608 = sqrt(r282607);
double r282609 = r282608 - r282602;
double r282610 = r282609 / r282605;
return r282610;
}



Bits error versus a



Bits error versus b_2



Bits error versus c
Initial program 1.7
Simplified1.7
Final simplification1.7
herbie shell --seed 2019152 +o rules:numerics
(FPCore (a b_2 c)
:name "quad2p (problem 3.2.1, positive)"
(/.p16 (+.p16 (neg.p16 b_2) (sqrt.p16 (-.p16 (*.p16 b_2 b_2) (*.p16 a c)))) a))