\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \cdot {k}^{\frac{-1}{2}}double f(double k, double n) {
double r5820791 = 1.0;
double r5820792 = k;
double r5820793 = sqrt(r5820792);
double r5820794 = r5820791 / r5820793;
double r5820795 = 2.0;
double r5820796 = atan2(1.0, 0.0);
double r5820797 = r5820795 * r5820796;
double r5820798 = n;
double r5820799 = r5820797 * r5820798;
double r5820800 = r5820791 - r5820792;
double r5820801 = r5820800 / r5820795;
double r5820802 = pow(r5820799, r5820801);
double r5820803 = r5820794 * r5820802;
return r5820803;
}
double f(double k, double n) {
double r5820804 = 2.0;
double r5820805 = atan2(1.0, 0.0);
double r5820806 = r5820804 * r5820805;
double r5820807 = n;
double r5820808 = r5820806 * r5820807;
double r5820809 = 1.0;
double r5820810 = k;
double r5820811 = r5820809 - r5820810;
double r5820812 = r5820811 / r5820804;
double r5820813 = pow(r5820808, r5820812);
double r5820814 = -0.5;
double r5820815 = pow(r5820810, r5820814);
double r5820816 = r5820813 * r5820815;
return r5820816;
}



Bits error versus k



Bits error versus n
Results
Initial program 0.4
rmApplied pow10.4
Applied sqrt-pow10.4
Applied pow-flip0.4
Simplified0.4
Final simplification0.4
herbie shell --seed 2019152 +o rules:numerics
(FPCore (k n)
:name "Migdal et al, Equation (51)"
(* (/ 1 (sqrt k)) (pow (* (* 2 PI) n) (/ (- 1 k) 2))))