0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r821299 = 0.5;
double r821300 = 2.0;
double r821301 = re;
double r821302 = r821301 * r821301;
double r821303 = im;
double r821304 = r821303 * r821303;
double r821305 = r821302 + r821304;
double r821306 = sqrt(r821305);
double r821307 = r821306 - r821301;
double r821308 = r821300 * r821307;
double r821309 = sqrt(r821308);
double r821310 = r821299 * r821309;
return r821310;
}
double f(double re, double im) {
double r821311 = re;
double r821312 = im;
double r821313 = hypot(r821311, r821312);
double r821314 = r821313 - r821311;
double r821315 = 2.0;
double r821316 = r821314 * r821315;
double r821317 = sqrt(r821316);
double r821318 = 0.5;
double r821319 = r821317 * r821318;
return r821319;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.2
Simplified13.3
Final simplification13.3
herbie shell --seed 2019152 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))