0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r503315 = 0.5;
double r503316 = 2.0;
double r503317 = re;
double r503318 = r503317 * r503317;
double r503319 = im;
double r503320 = r503319 * r503319;
double r503321 = r503318 + r503320;
double r503322 = sqrt(r503321);
double r503323 = r503322 - r503317;
double r503324 = r503316 * r503323;
double r503325 = sqrt(r503324);
double r503326 = r503315 * r503325;
return r503326;
}
double f(double re, double im) {
double r503327 = re;
double r503328 = im;
double r503329 = hypot(r503327, r503328);
double r503330 = r503329 - r503327;
double r503331 = 2.0;
double r503332 = r503330 * r503331;
double r503333 = sqrt(r503332);
double r503334 = 0.5;
double r503335 = r503333 * r503334;
return r503335;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.5
Simplified13.2
Final simplification13.2
herbie shell --seed 2019149 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))