Average Error: 58.7 → 0.0
Time: 9.8s
Precision: 64
\[-0.00017 \lt x\]
\[e^{x} - 1\]
\[\mathsf{expm1}\left(x\right)\]
e^{x} - 1
\mathsf{expm1}\left(x\right)
double f(double x) {
        double r2258727 = x;
        double r2258728 = exp(r2258727);
        double r2258729 = 1.0;
        double r2258730 = r2258728 - r2258729;
        return r2258730;
}

double f(double x) {
        double r2258731 = x;
        double r2258732 = expm1(r2258731);
        return r2258732;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original58.7
Target0.4
Herbie0.0
\[x \cdot \left(\left(1 + \frac{x}{2}\right) + \frac{x \cdot x}{6}\right)\]

Derivation

  1. Initial program 58.7

    \[e^{x} - 1\]
  2. Simplified0.0

    \[\leadsto \color{blue}{\mathsf{expm1}\left(x\right)}\]
  3. Final simplification0.0

    \[\leadsto \mathsf{expm1}\left(x\right)\]

Reproduce

herbie shell --seed 2019149 +o rules:numerics
(FPCore (x)
  :name "expm1 (example 3.7)"
  :pre (< -0.00017 x)

  :herbie-target
  (* x (+ (+ 1 (/ x 2)) (/ (* x x) 6)))

  (- (exp x) 1))