0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r653084 = 0.5;
double r653085 = 2.0;
double r653086 = re;
double r653087 = r653086 * r653086;
double r653088 = im;
double r653089 = r653088 * r653088;
double r653090 = r653087 + r653089;
double r653091 = sqrt(r653090);
double r653092 = r653091 - r653086;
double r653093 = r653085 * r653092;
double r653094 = sqrt(r653093);
double r653095 = r653084 * r653094;
return r653095;
}
double f(double re, double im) {
double r653096 = re;
double r653097 = im;
double r653098 = hypot(r653096, r653097);
double r653099 = r653098 - r653096;
double r653100 = 2.0;
double r653101 = r653099 * r653100;
double r653102 = sqrt(r653101);
double r653103 = 0.5;
double r653104 = r653102 * r653103;
return r653104;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.4
Simplified12.9
Final simplification12.9
herbie shell --seed 2019146 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))