0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r842496 = 0.5;
double r842497 = 2.0;
double r842498 = re;
double r842499 = r842498 * r842498;
double r842500 = im;
double r842501 = r842500 * r842500;
double r842502 = r842499 + r842501;
double r842503 = sqrt(r842502);
double r842504 = r842503 - r842498;
double r842505 = r842497 * r842504;
double r842506 = sqrt(r842505);
double r842507 = r842496 * r842506;
return r842507;
}
double f(double re, double im) {
double r842508 = re;
double r842509 = im;
double r842510 = hypot(r842508, r842509);
double r842511 = r842510 - r842508;
double r842512 = 2.0;
double r842513 = r842511 * r842512;
double r842514 = sqrt(r842513);
double r842515 = 0.5;
double r842516 = r842514 * r842515;
return r842516;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.2
Simplified13.2
Final simplification13.2
herbie shell --seed 2019138 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))