Average Error: 0.0 → 0.0
Time: 11.8s
Precision: 64
\[0 \le x \le 2\]
\[x \cdot \left(x \cdot x\right) + x \cdot x\]
\[x \cdot \left(x \cdot x + x\right)\]
x \cdot \left(x \cdot x\right) + x \cdot x
x \cdot \left(x \cdot x + x\right)
double f(double x) {
        double r3893861 = x;
        double r3893862 = r3893861 * r3893861;
        double r3893863 = r3893861 * r3893862;
        double r3893864 = r3893863 + r3893862;
        return r3893864;
}

double f(double x) {
        double r3893865 = x;
        double r3893866 = r3893865 * r3893865;
        double r3893867 = r3893866 + r3893865;
        double r3893868 = r3893865 * r3893867;
        return r3893868;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(\left(1.0 + x\right) \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(x \cdot x\right) + x \cdot x\]
  2. Using strategy rm
  3. Applied distribute-lft-out0.0

    \[\leadsto \color{blue}{x \cdot \left(x \cdot x + x\right)}\]
  4. Final simplification0.0

    \[\leadsto x \cdot \left(x \cdot x + x\right)\]

Reproduce

herbie shell --seed 2019134 
(FPCore (x)
  :name "Expression 3, p15"
  :pre (<= 0 x 2)

  :herbie-target
  (* (* (+ 1.0 x) x) x)

  (+ (* x (* x x)) (* x x)))