\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}{\left(\left(\pi \cdot 2\right) \cdot n\right)}^{\left(\frac{\frac{1}{2} - \frac{k}{2}}{2}\right)} \cdot \frac{{\left(\left(\pi \cdot 2\right) \cdot n\right)}^{\left(\frac{\frac{1}{2} - \frac{k}{2}}{2}\right)}}{\sqrt{k}}double f(double k, double n) {
double r6736920 = 1.0;
double r6736921 = k;
double r6736922 = sqrt(r6736921);
double r6736923 = r6736920 / r6736922;
double r6736924 = 2.0;
double r6736925 = atan2(1.0, 0.0);
double r6736926 = r6736924 * r6736925;
double r6736927 = n;
double r6736928 = r6736926 * r6736927;
double r6736929 = r6736920 - r6736921;
double r6736930 = r6736929 / r6736924;
double r6736931 = pow(r6736928, r6736930);
double r6736932 = r6736923 * r6736931;
return r6736932;
}
double f(double k, double n) {
double r6736933 = atan2(1.0, 0.0);
double r6736934 = 2.0;
double r6736935 = r6736933 * r6736934;
double r6736936 = n;
double r6736937 = r6736935 * r6736936;
double r6736938 = 0.5;
double r6736939 = k;
double r6736940 = r6736939 / r6736934;
double r6736941 = r6736938 - r6736940;
double r6736942 = r6736941 / r6736934;
double r6736943 = pow(r6736937, r6736942);
double r6736944 = sqrt(r6736939);
double r6736945 = r6736943 / r6736944;
double r6736946 = r6736943 * r6736945;
return r6736946;
}



Bits error versus k



Bits error versus n
Results
Initial program 0.4
Simplified0.4
rmApplied *-un-lft-identity0.4
Applied sqr-pow0.5
Applied times-frac0.5
Final simplification0.5
herbie shell --seed 2019133 +o rules:numerics
(FPCore (k n)
:name "Migdal et al, Equation (51)"
(* (/ 1 (sqrt k)) (pow (* (* 2 PI) n) (/ (- 1 k) 2))))