Average Error: 58.6 → 0.0
Time: 3.3s
Precision: 64
\[-0.00017 \lt x\]
\[e^{x} - 1\]
\[\mathsf{expm1}\left(x\right)\]
e^{x} - 1
\mathsf{expm1}\left(x\right)
double f(double x) {
        double r2703117 = x;
        double r2703118 = exp(r2703117);
        double r2703119 = 1.0;
        double r2703120 = r2703118 - r2703119;
        return r2703120;
}

double f(double x) {
        double r2703121 = x;
        double r2703122 = expm1(r2703121);
        return r2703122;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original58.6
Target0.5
Herbie0.0
\[x \cdot \left(\left(1 + \frac{x}{2}\right) + \frac{x \cdot x}{6}\right)\]

Derivation

  1. Initial program 58.6

    \[e^{x} - 1\]
  2. Simplified0.0

    \[\leadsto \color{blue}{\mathsf{expm1}\left(x\right)}\]
  3. Final simplification0.0

    \[\leadsto \mathsf{expm1}\left(x\right)\]

Reproduce

herbie shell --seed 2019133 +o rules:numerics
(FPCore (x)
  :name "expm1 (example 3.7)"
  :pre (< -0.00017 x)

  :herbie-target
  (* x (+ (+ 1 (/ x 2)) (/ (* x x) 6)))

  (- (exp x) 1))