0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r612183 = 0.5;
double r612184 = 2.0;
double r612185 = re;
double r612186 = r612185 * r612185;
double r612187 = im;
double r612188 = r612187 * r612187;
double r612189 = r612186 + r612188;
double r612190 = sqrt(r612189);
double r612191 = r612190 - r612185;
double r612192 = r612184 * r612191;
double r612193 = sqrt(r612192);
double r612194 = r612183 * r612193;
return r612194;
}
double f(double re, double im) {
double r612195 = re;
double r612196 = im;
double r612197 = hypot(r612195, r612196);
double r612198 = r612197 - r612195;
double r612199 = 2.0;
double r612200 = r612198 * r612199;
double r612201 = sqrt(r612200);
double r612202 = 0.5;
double r612203 = r612201 * r612202;
return r612203;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.6
Simplified13.4
Final simplification13.4
herbie shell --seed 2019132 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))