0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r537062 = 0.5;
double r537063 = 2.0;
double r537064 = re;
double r537065 = r537064 * r537064;
double r537066 = im;
double r537067 = r537066 * r537066;
double r537068 = r537065 + r537067;
double r537069 = sqrt(r537068);
double r537070 = r537069 - r537064;
double r537071 = r537063 * r537070;
double r537072 = sqrt(r537071);
double r537073 = r537062 * r537072;
return r537073;
}
double f(double re, double im) {
double r537074 = re;
double r537075 = im;
double r537076 = hypot(r537074, r537075);
double r537077 = r537076 - r537074;
double r537078 = 2.0;
double r537079 = r537077 * r537078;
double r537080 = sqrt(r537079);
double r537081 = 0.5;
double r537082 = r537080 * r537081;
return r537082;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.6
Simplified13.4
Final simplification13.4
herbie shell --seed 2019130 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))