0.5 \cdot \sqrt{2.0 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}\sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2.0} \cdot 0.5double f(double re, double im) {
double r527858 = 0.5;
double r527859 = 2.0;
double r527860 = re;
double r527861 = r527860 * r527860;
double r527862 = im;
double r527863 = r527862 * r527862;
double r527864 = r527861 + r527863;
double r527865 = sqrt(r527864);
double r527866 = r527865 - r527860;
double r527867 = r527859 * r527866;
double r527868 = sqrt(r527867);
double r527869 = r527858 * r527868;
return r527869;
}
double f(double re, double im) {
double r527870 = re;
double r527871 = im;
double r527872 = hypot(r527870, r527871);
double r527873 = r527872 - r527870;
double r527874 = 2.0;
double r527875 = r527873 * r527874;
double r527876 = sqrt(r527875);
double r527877 = 0.5;
double r527878 = r527876 * r527877;
return r527878;
}



Bits error versus re



Bits error versus im
Results
Initial program 37.9
Simplified13.6
Final simplification13.6
herbie shell --seed 2019129 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re)))))