\log \left(N + 1\right) - \log N
\begin{array}{l}
\mathbf{if}\;N \le 8885.992756934142:\\
\;\;\;\;\log \left(\frac{1 + N}{N}\right)\\
\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(\frac{-1}{2}, \left(\frac{\frac{1}{N}}{N}\right), \left(\mathsf{fma}\left(\frac{1}{3}, \left(\frac{\frac{\frac{1}{N}}{N}}{N}\right), \left(\frac{1}{N}\right)\right)\right)\right)\\
\end{array}double f(double N) {
double r1003905 = N;
double r1003906 = 1.0;
double r1003907 = r1003905 + r1003906;
double r1003908 = log(r1003907);
double r1003909 = log(r1003905);
double r1003910 = r1003908 - r1003909;
return r1003910;
}
double f(double N) {
double r1003911 = N;
double r1003912 = 8885.992756934142;
bool r1003913 = r1003911 <= r1003912;
double r1003914 = 1.0;
double r1003915 = r1003914 + r1003911;
double r1003916 = r1003915 / r1003911;
double r1003917 = log(r1003916);
double r1003918 = -0.5;
double r1003919 = r1003914 / r1003911;
double r1003920 = r1003919 / r1003911;
double r1003921 = 0.3333333333333333;
double r1003922 = r1003920 / r1003911;
double r1003923 = fma(r1003921, r1003922, r1003919);
double r1003924 = fma(r1003918, r1003920, r1003923);
double r1003925 = r1003913 ? r1003917 : r1003924;
return r1003925;
}



Bits error versus N
if N < 8885.992756934142Initial program 0.1
Simplified0.1
rmApplied log1p-udef0.1
Applied diff-log0.1
if 8885.992756934142 < N Initial program 59.4
Simplified59.4
rmApplied add-cbrt-cube59.4
Taylor expanded around inf 0.0
Simplified0.0
Final simplification0.1
herbie shell --seed 2019129 +o rules:numerics
(FPCore (N)
:name "2log (problem 3.3.6)"
(- (log (+ N 1)) (log N)))