Average Error: 5.7 → 0
Time: 4.3s
Precision: 64
\[e^{\log a + \log b}\]
\[a \cdot b\]
e^{\log a + \log b}
a \cdot b
double f(double a, double b) {
        double r2458947 = a;
        double r2458948 = log(r2458947);
        double r2458949 = b;
        double r2458950 = log(r2458949);
        double r2458951 = r2458948 + r2458950;
        double r2458952 = exp(r2458951);
        return r2458952;
}

double f(double a, double b) {
        double r2458953 = a;
        double r2458954 = b;
        double r2458955 = r2458953 * r2458954;
        return r2458955;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.7
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.7

    \[e^{\log a + \log b}\]
  2. Simplified0

    \[\leadsto \color{blue}{a \cdot b}\]
  3. Final simplification0

    \[\leadsto a \cdot b\]

Reproduce

herbie shell --seed 2019124 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))