Average Error: 0.0 → 0.0
Time: 13.2s
Precision: 64
\[56789 \le a \le 98765 \land 0 \le b \le 1 \land 0 \le c \le 0.0016773 \land 0 \le d \le 0.0016773\]
\[a \cdot \left(\left(b + c\right) + d\right)\]
\[\left(\left(b + c\right) + d\right) \cdot a\]
a \cdot \left(\left(b + c\right) + d\right)
\left(\left(b + c\right) + d\right) \cdot a
double f(double a, double b, double c, double d) {
        double r5725201 = a;
        double r5725202 = b;
        double r5725203 = c;
        double r5725204 = r5725202 + r5725203;
        double r5725205 = d;
        double r5725206 = r5725204 + r5725205;
        double r5725207 = r5725201 * r5725206;
        return r5725207;
}

double f(double a, double b, double c, double d) {
        double r5725208 = b;
        double r5725209 = c;
        double r5725210 = r5725208 + r5725209;
        double r5725211 = d;
        double r5725212 = r5725210 + r5725211;
        double r5725213 = a;
        double r5725214 = r5725212 * r5725213;
        return r5725214;
}

Error

Bits error versus a

Bits error versus b

Bits error versus c

Bits error versus d

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[a \cdot b + a \cdot \left(c + d\right)\]

Derivation

  1. Initial program 0.0

    \[a \cdot \left(\left(b + c\right) + d\right)\]
  2. Final simplification0.0

    \[\leadsto \left(\left(b + c\right) + d\right) \cdot a\]

Reproduce

herbie shell --seed 2019104 
(FPCore (a b c d)
  :name "Expression, p14"
  :pre (and (<= 56789 a 98765) (<= 0 b 1) (<= 0 c 0.0016773) (<= 0 d 0.0016773))

  :herbie-target
  (+ (* a b) (* a (+ c d)))

  (* a (+ (+ b c) d)))