- Split input into 2 regimes
if k < 8.476232649528033e+29
Initial program 0.1
\[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}\]
Simplified0.0
\[\leadsto \color{blue}{\frac{{k}^{m} \cdot a}{(\left(k + 10\right) \cdot k + 1)_*}}\]
- Using strategy
rm Applied *-un-lft-identity0.0
\[\leadsto \frac{{k}^{m} \cdot a}{\color{blue}{1 \cdot (\left(k + 10\right) \cdot k + 1)_*}}\]
Applied times-frac0.0
\[\leadsto \color{blue}{\frac{{k}^{m}}{1} \cdot \frac{a}{(\left(k + 10\right) \cdot k + 1)_*}}\]
Simplified0.0
\[\leadsto \color{blue}{{k}^{m}} \cdot \frac{a}{(\left(k + 10\right) \cdot k + 1)_*}\]
if 8.476232649528033e+29 < k
Initial program 5.7
\[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}\]
Simplified5.7
\[\leadsto \color{blue}{\frac{{k}^{m} \cdot a}{(\left(k + 10\right) \cdot k + 1)_*}}\]
Taylor expanded around -inf 63.0
\[\leadsto \color{blue}{\left(99 \cdot \frac{a \cdot e^{m \cdot \left(\log -1 - \log \left(\frac{-1}{k}\right)\right)}}{{k}^{4}} + \frac{a \cdot e^{m \cdot \left(\log -1 - \log \left(\frac{-1}{k}\right)\right)}}{{k}^{2}}\right) - 10 \cdot \frac{a \cdot e^{m \cdot \left(\log -1 - \log \left(\frac{-1}{k}\right)\right)}}{{k}^{3}}}\]
Simplified0.2
\[\leadsto \color{blue}{(\left(\frac{99}{k \cdot k}\right) \cdot \left(\frac{\frac{a}{k} \cdot e^{m \cdot \left(0 + \log k\right)}}{k}\right) + \left(-10 \cdot \frac{\frac{\frac{a}{k} \cdot e^{m \cdot \left(0 + \log k\right)}}{k}}{k}\right))_* + \frac{\frac{a}{k} \cdot e^{m \cdot \left(0 + \log k\right)}}{k}}\]
- Recombined 2 regimes into one program.
Final simplification0.1
\[\leadsto \begin{array}{l}
\mathbf{if}\;k \le 8.476232649528033 \cdot 10^{+29}:\\
\;\;\;\;{k}^{m} \cdot \frac{a}{(\left(k + 10\right) \cdot k + 1)_*}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{a}{k} \cdot e^{m \cdot \log k}}{k} + (\left(\frac{99}{k \cdot k}\right) \cdot \left(\frac{\frac{a}{k} \cdot e^{m \cdot \log k}}{k}\right) + \left(\frac{\frac{\frac{a}{k} \cdot e^{m \cdot \log k}}{k}}{k} \cdot -10\right))_*\\
\end{array}\]