- Split input into 2 regimes
if x < -11423.365833095679 or 12602.174557478349 < x
Initial program 59.2
\[\frac{x}{x + 1} - \frac{x + 1}{x - 1}\]
- Using strategy
rm Applied div-inv59.3
\[\leadsto \frac{x}{x + 1} - \color{blue}{\left(x + 1\right) \cdot \frac{1}{x - 1}}\]
Taylor expanded around -inf 0.3
\[\leadsto \color{blue}{-\left(3 \cdot \frac{1}{{x}^{3}} + \left(\frac{1}{{x}^{2}} + 3 \cdot \frac{1}{x}\right)\right)}\]
Simplified0.0
\[\leadsto \color{blue}{\left(\frac{-3}{x} - \frac{1}{x \cdot x}\right) + \frac{\frac{-3}{x}}{x \cdot x}}\]
if -11423.365833095679 < x < 12602.174557478349
Initial program 0.1
\[\frac{x}{x + 1} - \frac{x + 1}{x - 1}\]
- Using strategy
rm Applied div-inv0.1
\[\leadsto \frac{x}{x + 1} - \color{blue}{\left(x + 1\right) \cdot \frac{1}{x - 1}}\]
- Using strategy
rm Applied flip-+0.1
\[\leadsto \frac{x}{x + 1} - \color{blue}{\frac{x \cdot x - 1 \cdot 1}{x - 1}} \cdot \frac{1}{x - 1}\]
Applied frac-times0.1
\[\leadsto \frac{x}{x + 1} - \color{blue}{\frac{\left(x \cdot x - 1 \cdot 1\right) \cdot 1}{\left(x - 1\right) \cdot \left(x - 1\right)}}\]
Applied frac-sub0.1
\[\leadsto \color{blue}{\frac{x \cdot \left(\left(x - 1\right) \cdot \left(x - 1\right)\right) - \left(x + 1\right) \cdot \left(\left(x \cdot x - 1 \cdot 1\right) \cdot 1\right)}{\left(x + 1\right) \cdot \left(\left(x - 1\right) \cdot \left(x - 1\right)\right)}}\]
Simplified0.1
\[\leadsto \frac{\color{blue}{\left(\left(x + -1\right) \cdot \left(x + -1\right)\right) \cdot x - \left(x + -1\right) \cdot \left(\left(1 + x\right) \cdot \left(1 + x\right)\right)}}{\left(x + 1\right) \cdot \left(\left(x - 1\right) \cdot \left(x - 1\right)\right)}\]
- Recombined 2 regimes into one program.
Final simplification0.1
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le -11423.365833095679 \lor \neg \left(x \le 12602.174557478349\right):\\
\;\;\;\;\left(\frac{-3}{x} - \frac{1}{x \cdot x}\right) + \frac{\frac{-3}{x}}{x \cdot x}\\
\mathbf{else}:\\
\;\;\;\;\frac{\left(\left(-1 + x\right) \cdot \left(-1 + x\right)\right) \cdot x - \left(-1 + x\right) \cdot \left(\left(1 + x\right) \cdot \left(1 + x\right)\right)}{\left(\left(x - 1\right) \cdot \left(x - 1\right)\right) \cdot \left(1 + x\right)}\\
\end{array}\]