- Split input into 2 regimes
if y < -2.3635533604117678e-104 or 1.551706070831678e-271 < y
Initial program 1.5
\[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}\]
- Using strategy
rm Applied associate-/l*1.3
\[\leadsto \color{blue}{\frac{x}{\frac{y}{e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}}}\]
if -2.3635533604117678e-104 < y < 1.551706070831678e-271
Initial program 4.7
\[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}\]
Taylor expanded around inf 4.7
\[\leadsto \frac{x \cdot \color{blue}{e^{1.0 \cdot \log \left(\frac{1}{a}\right) - \left(\log \left(\frac{1}{z}\right) \cdot y + \left(b + t \cdot \log \left(\frac{1}{a}\right)\right)\right)}}}{y}\]
Simplified10.5
\[\leadsto \frac{x \cdot \color{blue}{\left(\left({z}^{y} \cdot e^{-b}\right) \cdot \left({a}^{t} \cdot {a}^{\left(-1.0\right)}\right)\right)}}{y}\]
- Using strategy
rm Applied pow-neg10.5
\[\leadsto \frac{x \cdot \left(\left({z}^{y} \cdot e^{-b}\right) \cdot \left({a}^{t} \cdot \color{blue}{\frac{1}{{a}^{1.0}}}\right)\right)}{y}\]
Applied un-div-inv10.5
\[\leadsto \frac{x \cdot \left(\left({z}^{y} \cdot e^{-b}\right) \cdot \color{blue}{\frac{{a}^{t}}{{a}^{1.0}}}\right)}{y}\]
Applied exp-neg10.5
\[\leadsto \frac{x \cdot \left(\left({z}^{y} \cdot \color{blue}{\frac{1}{e^{b}}}\right) \cdot \frac{{a}^{t}}{{a}^{1.0}}\right)}{y}\]
Applied un-div-inv10.5
\[\leadsto \frac{x \cdot \left(\color{blue}{\frac{{z}^{y}}{e^{b}}} \cdot \frac{{a}^{t}}{{a}^{1.0}}\right)}{y}\]
Applied frac-times10.5
\[\leadsto \frac{x \cdot \color{blue}{\frac{{z}^{y} \cdot {a}^{t}}{e^{b} \cdot {a}^{1.0}}}}{y}\]
Applied associate-*r/10.5
\[\leadsto \frac{\color{blue}{\frac{x \cdot \left({z}^{y} \cdot {a}^{t}\right)}{e^{b} \cdot {a}^{1.0}}}}{y}\]
- Recombined 2 regimes into one program.
Final simplification3.1
\[\leadsto \begin{array}{l}
\mathbf{if}\;y \le -2.3635533604117678 \cdot 10^{-104} \lor \neg \left(y \le 1.551706070831678 \cdot 10^{-271}\right):\\
\;\;\;\;\frac{x}{\frac{y}{e^{\left(\log a \cdot \left(t - 1.0\right) + \log z \cdot y\right) - b}}}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{x \cdot \left({z}^{y} \cdot {a}^{t}\right)}{e^{b} \cdot {a}^{1.0}}}{y}\\
\end{array}\]