Initial program 0.0
\[\frac{-\left(f + n\right)}{f - n}\]
Initial simplification0.0
\[\leadsto -\frac{n + f}{f - n}\]
- Using strategy
rm Applied *-un-lft-identity0.0
\[\leadsto -\frac{\color{blue}{1 \cdot \left(n + f\right)}}{f - n}\]
Applied associate-/l*0.0
\[\leadsto -\color{blue}{\frac{1}{\frac{f - n}{n + f}}}\]
- Using strategy
rm Applied add-cbrt-cube0.0
\[\leadsto -\color{blue}{\sqrt[3]{\left(\frac{1}{\frac{f - n}{n + f}} \cdot \frac{1}{\frac{f - n}{n + f}}\right) \cdot \frac{1}{\frac{f - n}{n + f}}}}\]
- Using strategy
rm Applied add-cube-cbrt0.0
\[\leadsto -\sqrt[3]{\left(\color{blue}{\left(\left(\sqrt[3]{\frac{1}{\frac{f - n}{n + f}}} \cdot \sqrt[3]{\frac{1}{\frac{f - n}{n + f}}}\right) \cdot \sqrt[3]{\frac{1}{\frac{f - n}{n + f}}}\right)} \cdot \frac{1}{\frac{f - n}{n + f}}\right) \cdot \frac{1}{\frac{f - n}{n + f}}}\]
Applied associate-*l*0.0
\[\leadsto -\sqrt[3]{\color{blue}{\left(\left(\sqrt[3]{\frac{1}{\frac{f - n}{n + f}}} \cdot \sqrt[3]{\frac{1}{\frac{f - n}{n + f}}}\right) \cdot \left(\sqrt[3]{\frac{1}{\frac{f - n}{n + f}}} \cdot \frac{1}{\frac{f - n}{n + f}}\right)\right)} \cdot \frac{1}{\frac{f - n}{n + f}}}\]
Simplified0.0
\[\leadsto -\sqrt[3]{\left(\color{blue}{\left(\sqrt[3]{\frac{f + n}{f - n}} \cdot \sqrt[3]{\frac{f + n}{f - n}}\right)} \cdot \left(\sqrt[3]{\frac{1}{\frac{f - n}{n + f}}} \cdot \frac{1}{\frac{f - n}{n + f}}\right)\right) \cdot \frac{1}{\frac{f - n}{n + f}}}\]
- Using strategy
rm Applied add-cube-cbrt0.1
\[\leadsto -\sqrt[3]{\left(\left(\sqrt[3]{\frac{f + n}{f - n}} \cdot \sqrt[3]{\frac{f + n}{f - n}}\right) \cdot \left(\sqrt[3]{\frac{1}{\frac{f - n}{n + f}}} \cdot \frac{1}{\frac{f - n}{n + f}}\right)\right) \cdot \frac{1}{\color{blue}{\left(\sqrt[3]{\frac{f - n}{n + f}} \cdot \sqrt[3]{\frac{f - n}{n + f}}\right) \cdot \sqrt[3]{\frac{f - n}{n + f}}}}}\]
Final simplification0.1
\[\leadsto -\sqrt[3]{\frac{1}{\left(\sqrt[3]{\frac{f - n}{n + f}} \cdot \sqrt[3]{\frac{f - n}{n + f}}\right) \cdot \sqrt[3]{\frac{f - n}{n + f}}} \cdot \left(\left(\frac{1}{\frac{f - n}{n + f}} \cdot \sqrt[3]{\frac{1}{\frac{f - n}{n + f}}}\right) \cdot \left(\sqrt[3]{\frac{n + f}{f - n}} \cdot \sqrt[3]{\frac{n + f}{f - n}}\right)\right)}\]