- Split input into 2 regimes
if x < -0.006528557608830371 or 0.00677807468883077 < x
Initial program 0.0
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
- Using strategy
rm Applied flip--0.0
\[\leadsto \color{blue}{\frac{\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}} - 1 \cdot 1}{\frac{2}{1 + e^{-2 \cdot x}} + 1}}\]
- Using strategy
rm Applied add-log-exp0.0
\[\leadsto \frac{\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}} - \color{blue}{\log \left(e^{1 \cdot 1}\right)}}{\frac{2}{1 + e^{-2 \cdot x}} + 1}\]
Applied add-log-exp0.0
\[\leadsto \frac{\color{blue}{\log \left(e^{\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}}\right)} - \log \left(e^{1 \cdot 1}\right)}{\frac{2}{1 + e^{-2 \cdot x}} + 1}\]
Applied diff-log0.0
\[\leadsto \frac{\color{blue}{\log \left(\frac{e^{\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}}}{e^{1 \cdot 1}}\right)}}{\frac{2}{1 + e^{-2 \cdot x}} + 1}\]
Simplified0.0
\[\leadsto \frac{\log \color{blue}{\left(e^{(\left(\frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \left(\frac{2}{1 + e^{-2 \cdot x}}\right) + -1)_*}\right)}}{\frac{2}{1 + e^{-2 \cdot x}} + 1}\]
- Using strategy
rm Applied add-cbrt-cube0.0
\[\leadsto \frac{\log \left(e^{(\left(\frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \left(\frac{2}{1 + e^{-2 \cdot x}}\right) + -1)_*}\right)}{\color{blue}{\sqrt[3]{\left(\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \frac{2}{1 + e^{-2 \cdot x}}}} + 1}\]
if -0.006528557608830371 < x < 0.00677807468883077
Initial program 59.0
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
Taylor expanded around 0 0.0
\[\leadsto \color{blue}{\left(x + \frac{2}{15} \cdot {x}^{5}\right) - \frac{1}{3} \cdot {x}^{3}}\]
- Recombined 2 regimes into one program.
Final simplification0.0
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le -0.006528557608830371 \lor \neg \left(x \le 0.00677807468883077\right):\\
\;\;\;\;\frac{\log \left(e^{(\left(\frac{2}{e^{-2 \cdot x} + 1}\right) \cdot \left(\frac{2}{e^{-2 \cdot x} + 1}\right) + -1)_*}\right)}{1 + \sqrt[3]{\left(\frac{2}{e^{-2 \cdot x} + 1} \cdot \frac{2}{e^{-2 \cdot x} + 1}\right) \cdot \frac{2}{e^{-2 \cdot x} + 1}}}\\
\mathbf{else}:\\
\;\;\;\;\left({x}^{5} \cdot \frac{2}{15} + x\right) - {x}^{3} \cdot \frac{1}{3}\\
\end{array}\]