- Split input into 2 regimes
if x < -12713.063048510125 or 12649.733194213431 < x
Initial program 59.3
\[\frac{x}{x + 1} - \frac{x + 1}{x - 1}\]
Taylor expanded around -inf 0.3
\[\leadsto \color{blue}{-\left(3 \cdot \frac{1}{{x}^{3}} + \left(\frac{1}{{x}^{2}} + 3 \cdot \frac{1}{x}\right)\right)}\]
Simplified0.0
\[\leadsto \color{blue}{\left(\frac{-3}{x} - \frac{1}{x \cdot x}\right) + \frac{\frac{-3}{x}}{x \cdot x}}\]
if -12713.063048510125 < x < 12649.733194213431
Initial program 0.1
\[\frac{x}{x + 1} - \frac{x + 1}{x - 1}\]
- Using strategy
rm Applied add-cube-cbrt0.1
\[\leadsto \color{blue}{\left(\sqrt[3]{\frac{x}{x + 1} - \frac{x + 1}{x - 1}} \cdot \sqrt[3]{\frac{x}{x + 1} - \frac{x + 1}{x - 1}}\right) \cdot \sqrt[3]{\frac{x}{x + 1} - \frac{x + 1}{x - 1}}}\]
- Using strategy
rm Applied add-cbrt-cube0.1
\[\leadsto \left(\sqrt[3]{\frac{x}{x + 1} - \frac{x + 1}{x - 1}} \cdot \sqrt[3]{\color{blue}{\sqrt[3]{\left(\left(\frac{x}{x + 1} - \frac{x + 1}{x - 1}\right) \cdot \left(\frac{x}{x + 1} - \frac{x + 1}{x - 1}\right)\right) \cdot \left(\frac{x}{x + 1} - \frac{x + 1}{x - 1}\right)}}}\right) \cdot \sqrt[3]{\frac{x}{x + 1} - \frac{x + 1}{x - 1}}\]
- Using strategy
rm Applied add-log-exp0.1
\[\leadsto \left(\sqrt[3]{\frac{x}{x + 1} - \frac{x + 1}{x - 1}} \cdot \sqrt[3]{\sqrt[3]{\left(\left(\frac{x}{x + 1} - \frac{x + 1}{x - 1}\right) \cdot \color{blue}{\log \left(e^{\frac{x}{x + 1} - \frac{x + 1}{x - 1}}\right)}\right) \cdot \left(\frac{x}{x + 1} - \frac{x + 1}{x - 1}\right)}}\right) \cdot \sqrt[3]{\frac{x}{x + 1} - \frac{x + 1}{x - 1}}\]
- Recombined 2 regimes into one program.
Final simplification0.1
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le -12713.063048510125 \lor \neg \left(x \le 12649.733194213431\right):\\
\;\;\;\;\left(\frac{-3}{x} - \frac{1}{x \cdot x}\right) + \frac{\frac{-3}{x}}{x \cdot x}\\
\mathbf{else}:\\
\;\;\;\;\left(\sqrt[3]{\sqrt[3]{\left(\frac{x}{1 + x} - \frac{1 + x}{x - 1}\right) \cdot \left(\log \left(e^{\frac{x}{1 + x} - \frac{1 + x}{x - 1}}\right) \cdot \left(\frac{x}{1 + x} - \frac{1 + x}{x - 1}\right)\right)}} \cdot \sqrt[3]{\frac{x}{1 + x} - \frac{1 + x}{x - 1}}\right) \cdot \sqrt[3]{\frac{x}{1 + x} - \frac{1 + x}{x - 1}}\\
\end{array}\]